441=7m^2

Solution for 441=7m^2 equation:

441=7m^2

We move all terms to the left:

441-(7m^2)=0

a = -7; b = 0; c = +441;
Δ = b2-4ac
Δ = 02-4·(-7)·441
Δ = 12348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12348}=\sqrt{1764*7}=\sqrt{1764}*\sqrt{7}=42\sqrt{7}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42\sqrt{7}}{2*-7}=\frac{0-42\sqrt{7}}{-14}
=-\frac{42\sqrt{7}}{-14}
=-\frac{3\sqrt{7}}{-1}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42\sqrt{7}}{2*-7}=\frac{0+42\sqrt{7}}{-14}
=\frac{42\sqrt{7}}{-14}
=\frac{3\sqrt{7}}{-1}
$